UNIDAD II TIPOS DE DATOS ESTRUCTURADOS

//PROGRAMA 1//
#include <iostream.h>
#include <conio.h>
int main()
{
clrscr();
const int MAXTEMPS = 5;
int i, temp[MAXTEMPS];
for (i = 0; i < MAXTEMPS; i++)
{
cout << "introduzca una temperatura: ";
cin>> temp[i];
}
cout << endl;
for (i = 0; i < MAXTEMPS; i++)
cout << "la temperatura " << i <<" " << "es: " << temp[i] << endl;
getch();
return 0;
}

//PROGRAMA 2
#include <iostream.h>
#include <conio.h>
int main()
{
//clrscr();
const int MAXTEMPS = 5;
int i, temp[MAXTEMPS], total = 0;
for (i = 0; i < MAXTEMPS; i++)
{
cout << "introduzca una temperatura: ";
cin>> temp[i];
}
cout << "\nEl total de las temperaturas";
for (i = 0; i < MAXTEMPS; i++)
{
cout << " " << temp[i];
total = total + temp[i];
}
cout << " es " << total <<endl;
getch();
return 0;
}

//PROGRAMA 3
#include <iostream.h>
#include <conio.h>
int main()
{
//clrscr();
const int MAXELS = 5;
int i, max, nums[MAXELS] = {2, 18, 1, 27, 16};
max = nums[0];
for (i = 1; i < MAXELS; i++)
if (max < nums[i])
max = nums[i];
cout << "El maximo valor es : " << max << endl;
getch();
return 0;
}

//PROGRAMA 4
// Suma de dos vectores
#include <iostream.h>
#include <conio.h>
#include <stdio.h>
 main()
{
//clrscr();
const int lim = 5;
int A[lim], B[lim], C[lim], i;
cout << "Dame los " << lim << " valores del arreglo A, "
<< "separados por espacios: ";
for (i = 0; i < lim; i++) cin >> A[i];
cout << "\nDame los " << lim << " valores del arreglo B, "
<< "separados por espacios: ";
for (i = 0; i < lim; i++) cin >> B[i];
cout << "\nLa suma es: " << endl;
for (i = 0; i<lim; i++)
{
C[i] = A[i] + B[i];
cout << C[i] << endl;
}
getch();5
}

//ROGRAMA 5
#include <iostream.h>
#include <conio.h>
#include <stdio.h>
#include <iomanip.h>
int main()
{
//clrscr();
const int NUMRENG = 3;
const int NUMCOL = 4;
int i,j;
int val[NUMRENG][NUMCOL] = {8, 16, 9, 52, 3, 15, 27, 6, 14,
25, 2, 10};
cout << "\nDespliegue del arreglo val por elemento explicito" <<endl
<< "\n" << setw(4) << val[0][0] << setw(4) << val[0][1]
<< setw(4) << val[0][2] << setw(4) << val[0][3]
<< "\n" << setw(4) << val[1][0] << setw(4) << val[1][1]
<< setw(4) << val[1][2] << setw(4) << val[1][3]
<< "\n" << setw(4) << val[2][0] << setw(4) << val[2][1]
<< setw(4) << val[2][2] << setw(4) << val[2][3];
cout << "\n\nDespliegue del arreglo val empleando ciclos for anidados" <<
endl;
for (i = 0; i < NUMRENG; i++)
{
cout << "\n";
for (j = 0; j < NUMCOL; j++)
cout << setw(4) << val[i][j];
}
cout << endl;
getch();
return 0;
}

//0PROGRAMA 6
#include <iostream.h>
#include <conio.h>
#include <stdio.h>
#include <iomanip.h>
int main()
{
//clrscr();
const int NUMRENG = 3;
const int NUMCOL = 4;
int i,j;
int val[NUMRENG][NUMCOL] = {8, 16, 9, 52, 3, 15, 27, 6, 14,
25, 2, 10};
//multiplicar cada elemento por 10 y desplegarlo
cout << "\nDesplegar los elementos multiplicados";
for (i = 0; i < NUMRENG; i++)
{
cout << endl;
for (j = 0; j < NUMCOL; j++)
{
val[i][j] = val[i][j] * 10;
cout << setw(5) << val[i][j];
}
}
cout << endl;
getch();
return 0;
}